Correct Answer - Option 1 : 115 mm
Concept:
Maximum shear stress for solid shaft is given by:
τmax = \(\frac{{16{\rm{T}}}}{{{\rm{\pi }}{{\rm{d}}^3}}}\)
Calculation:
Given:
T = 18000 Nm, τ = 60 N/mm2
60 = \(\frac{{16{\rm{}} \times 18000 \times 1000}}{{{\rm{\pi }} \times {{\rm{d}}^3}}}\)
d = 115.17 mm
Therefore, diameter of the shaft is 115 mm.