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A computer employs RAM chips of 256 bytes and ROM chips of 1024 bytes. If the computer system needs 1kB of RAM and 1kB of ROM, then how many address lines are required to access the memory?
1. 10
2. 11
3. 12
4. 13

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Correct Answer - Option 2 : 11

Concept:

An ‘n’ bit address can access a total of 2memory locations.

Calculation:

RAM - 256 B

ROM - 1024 B i.e. 1kB

1 kB of RAM and 1 kB of ROM total 2kB

∴ 2n = 2 kB = 211

n = 11 (bits are required)

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