Correct Answer - Option 2 : 2 poles and 2 zeros
Concept:
Bode plot transfer function is represented in standard time constant form as
\(T\left( s \right) = \frac{{k\left( {\frac{s}{{{\omega _{{c_1}}}}} + 1} \right) \ldots }}{{\left( {\frac{s}{{{\omega _{{c_2}}}}} + 1} \right)\left( {\frac{s}{{{\omega _{{c_3}}}}} + 1} \right) \ldots }}\)
ωc1, ωc2, … are corner frequencies.
In a Bode magnitude plot,
- For a pole at the origin, the initial slope is -20 dB/decade
- For a zero at the origin, the initial slope is 20 dB/decade
- The slope of magnitude plot changes at each corner frequency
- The corner frequency associated with poles causes a slope of -20 dB/decade
- The corner frequency associated with poles causes a slope of -20 dB/decade
- The final slope of Bode magnitude plot = (Z – P) × 20 dB/decade
Where Z is the number zeros and P is the number of poles.
Calculation:
As per the given details bode plot is:
DIAGRAM
The initial Slope of -40 dB indicates 2 poles at Origin.
The final slope of 0 dB indicates that 2 more zeros are there in the system.
Hence,
P = Z = 2