Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.5k views
in Mathematics by (24.1k points)

Find the equations to the tangents to the conic x2 + 4xy + 3y2 - 5x - 6y + 3 = 0 which are parallel to the straight line x + 4y = 0.

1 Answer

+1 vote
by (34.4k points)
selected by
 
Best answer

x2 + 4xy + 3y2 - 5x - 6y + 3 = 0...(1)

The equation to any such tangent is

x + 4y + c = 0.........(2),

where c is to be determined.

This straight line meets (1) in points given by

The roots of this equation are equal, i.e. the line (2) is a tangent, if

The required tangents are therefore

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...