Correct Answer - Option 4 : 1111 1111 1110 1000
Option 1:
Since 1111 1111 1110 1011 is in 2’ complement number system it can be written as 101011
Decimal of this binary -32 x 1 + 16 x 0 + 8 x 1 + 4 x 0 + 2 x 1 + 1 x 1 = -32 + 8 + 2 + 1 = -21
Option 2:
Since 1111 1111 1110 1001 is in 2’ complement number system it can be written as 10 1001
Decimal value of above binary: -32 x 1+ 16 x 0 + 8 x 1 + 4 x 0 + 2 x 0 + 1 x 1 = -32 + 8 + 1 = -23
Option 3:
Since 1111 1111 1110 0111 is in 2’ complement number system it can be written as 10 0111
Decimal value of above binary: -32 x 1 + 16 x 0 + 8 x 0 + 4 x 1 + 2 x 1 + 1 x 1 = -32 + 4 + 2 + 1 = -25
Option 4:
Since 1111 1111 1110 1000 is in 2’ complement number system it can be written as 101000
Decimal value of above binary: -32 x 1 + 16 x 0 + 8 x 1 + 0 + 0 + 0 = -32 + 8 = -24
Therefore option 4 is the correct answer.