Correct Answer - Option 2 : 6°
Solution:
Given
Time taken by stage I (T1) = 1 ms
Time taken by stage II (T2) = 1.5 ms
Speed of engine = 1000 rpm
Spark advance time = T2 – T1 = 1.5 – 1 = 0.5 ms
Now, If the speed of the engine is doubled, N = 2000 rpm
then, additional spark advance necessary will be
Speed - 2000 rpm → 4000π degrees per minute → 4000π/60 degrees per sec
Spark advance time is 0.5 ms → 0.5 × 10-3 × (4000 × 180/60) degrees = 6°