Correct Answer - Option 4 :
110/3 seconds
Given:
Speed of larger train = 72 km/hr
Speed of shorter train = 54 km/hr
Length of shorter train = Length of larger train – 50
Time to cross platform by larger train = 30 seconds
Concept used:
Distance = Speed × Time
And, Length of train + Length of platform = Total distance
Speed in m/s = 5/18 × Speed in km/hr
Calculation:
Let length of larger train be L and length of platform be P
∴ Length of shorter train = L – 50
Time taken by shorter train = T
Now, Total distance covered by larger train = L + P
Speed of larger train = 72 km/hr
Speed of larger train in m/s = 72 × 5/18
⇒ Speed of larger train = 20 m/s
Time taken to cover the distance = 30 seconds
So, Distance = Speed × Time
⇒ L + P = 30 × 20
⇒ L + P = 600 ----(i)
Now, length of shorter train = L – 50
Total distance covered by shorter train = L – 50 + P
Speed of shorter train = 54 km/hr
Speed of shorter train in m/s = 54 × 5/18
⇒ Speed of shorter train in m/s = 15 m/s
Time taken by shorter train = T
So, Distance = Speed × Time
⇒ L + P – 50 = 15 × T ----(ii)
Now, putting value of equation (i) and (ii)
⇒ 600 – 50 = 15T
⇒ 15T = 550
⇒ T = 550/15
⇒ T = 110/3 seconds
∴ Time taken by shorter train to cover the platform
= 110/3 seconds