Correct Answer - Option 2 : 0.268
Concept:
The efficiency of the Carnot Engine:
\(η = \frac{{{T_H} - {T_L}}}{{{T_H}}} = 1 - \frac{{{T_L}}}{{{T_H}}}\)
The efficiency of the Carnot cycle is the function of source (TH) and sink (TL) temperature.
Carnot cycle efficiency depends upon the temperature range of operation.
Calculation:
Given:
TH = 373 K, TL = 273 K
Therefore, \(\eta =1-\frac{273}{373} = 0.268\)
