Correct Answer - Option 4 : 8 π
Concept:
Power transmitted by the shaft,
\(P = T.\omega = \frac{{2\pi NT}}{{60}}\;watts\)
where, ω = angular speed radians/sec, T = external torque applied N-m, N = number of revolutions per minute
Calculations:
Given:
Number of revolution per minute N = 160 rpm, Torque T = 1500 Nm
\(P = 2\pi \times 160 \times \frac{{1500}}{{60}}\;watss = 8\pi \;kW\)