Correct Answer - Option 1 : 20 days
Concept:
Expected duration \(\left( {{t_e}} \right) = \frac{{{t_0} + 4{t_m} + {t_p}}}{6}\)
Where, t0 = optimistic duration
tm = Most likely duration
tp = Pessimistic duration
Calculation:
t0 = 16 days, tp = 28 days, tm = 19 days
\({t_e} = \frac{{{t_0} + 4{t_m} + {t_p}}}{6} = \frac{{16 + \left( {4 \times 19} \right) + 28}}{6}\)
\( = \frac{{16 + 76 + 28}}{6} = \frac{{120}}{6} = 20\;days\)