Correct Answer - Option 2 : 35 grams
CONCEPT:
- The specific gravity of a substance is the ratio of the density of a substance to the density of water or any other reference substance.
\( specific \ gravity= \frac{ρ_{Given substance}}{ρ _{Reference Substance}}\)
- Archimedes's principle states that "upward buoyant force exerted by a fluid on a body which is immersed in a fluid, whether partially or fully submerged, is equal to the weight of the fluid that the body displaces and acts in the upward direction "
CALCULATION:
Given- Equivalent weight in water = mg = 40g, Actual weight = mg = 50 g, ρwater = 1 g/cm3, and Specific gravity of liquid (ρliquid) = 1.5
- The upward thrust acting on the object is given by
⇒ Actual weight - Buoyant force = Equivalent weight in water
⇒ 50g - ρwaterVg = 40g
⇒ ρwaterVg = 10 g
⇒ V =10 Cm3
- The weight of the body in a liquid of specific gravity 1.5 is
⇒ Actual weight - Buoyant force = weight in liquid
⇒ 50 - ρliquidVg = 50 - 1.5 × 10 = 35g
- Hence, option 2 is the answer