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There are two generators in a power system. No-load frequencies of the generators are 51.5 Hz and 51 Hz, respectively, and both are having droop constant of 1 Hz/MW. Total load in the system is 2.5 MW. Assuming that the generators are operating under their respective droop characteristics, the frequency of the power system in Hz in the steady state is _____

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Given that the generators are in parallel and operate at the same frequency (f) at a steady loss.

Let load on generator G1 is P1 and on G2 is P2.

Then for G1 generator

\(\frac{{51.5 - f}}{{{P_1}}}\;\) = constant droop

\( \Rightarrow \frac{{51.5 - f}}{{{P_1}}} = 1\) 

⇒ 51.5 – f = P1          ---(1)

Now, in steady-state load is 2.5 MW

So, load by G2 is (2.5 – P1)

For G2, \(\frac{{51 - f}}{{2.5{P_1}}} = 1\) 

⇒ 51 – f = 2.5 – P1      ---(2)

From equation (1) and (2),

51.5 – f + 51 – f = P1 + 2.5 – P1

⇒ 102.5 – 2f = 2.5

⇒ f = 50 Hz

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