Given that the generators are in parallel and operate at the same frequency (f) at a steady loss.
Let load on generator G1 is P1 and on G2 is P2.
Then for G1 generator
\(\frac{{51.5 - f}}{{{P_1}}}\;\) = constant droop
\( \Rightarrow \frac{{51.5 - f}}{{{P_1}}} = 1\)
⇒ 51.5 – f = P1 ---(1)
Now, in steady-state load is 2.5 MW
So, load by G2 is (2.5 – P1)
For G2, \(\frac{{51 - f}}{{2.5{P_1}}} = 1\)
⇒ 51 – f = 2.5 – P1 ---(2)
From equation (1) and (2),
51.5 – f + 51 – f = P1 + 2.5 – P1
⇒ 102.5 – 2f = 2.5
⇒ f = 50 Hz