Correct Answer - Option 3 : 0.042 Wb
Given that, number of poles (P) = 6
Speed (N) = 1000
Number of conductors (Z) = 240
Number of parallel paths (A) = 2
Induced emf (E) = 500 V
Now \(E = \frac{{\phi ZNP}}{{60A}}\)
\( \Rightarrow \varphi = \frac{{500\; \times \;600\; \times \;2}}{{6\; \times \;1000\; \times \;240}}\)
\(\Rightarrow \varphi = \frac{1}{{24}} = 0.042Wb\)