Correct Answer - Option 1 : 2.5 kHz
Concept:
Conversion Rate / Sampling frequency is mathematically given by:
\(= \frac{1}{{Conversion\;time}}\)
The maximum input frequency is:
\( = \frac{{{f_s}}}{2}\)
\(= \frac{1}{{2\;conversion\;time}}\)
Calculation:
Given, Conversion time = 200 μsec
Maximum input frequency will be:
\(= \frac{1}{{2 \times 200 \times {{10}^{ - 6}}}}\)
\( = \frac{{{{10}^4}}}{4}\)
\( = \frac{{10}}{4}KHz\)
= 2.5 kHz
