Correct Answer - Option 4 : 0.34%
Concept:
Grade compensation for a railway track is given as follows-
For B.G = 0.04% per degree of curve
M.G = 0.03% per degree of curve
N.G = 0.02% per degree of curve
Compensated gradient = Ruling gradient- Grade compensation
Calculation:
Ruling gradient = 1 in 200
Degree of curve = 4°
Grade compensation= (0.04x4)/100
Compensated gradient = (1/200) - (0.16/100) = 0.34%