Correct Answer - Option 1 : 224.4 rpm
Concept:
The specific speed of a turbine is defined as, the speed of a geometrically similar Turbine that would develop unit power when working under a unit head (1 m head). Is prescribed by the relation. \({N_s} = \frac{{N\sqrt P }}{{{H^{\frac{5}{4}}}}}\)
Calculation:
By specific speed, we understand the speed of geometrically similar turbines which would develop 1 kW power when operated under 1 m head.
P = 8000 kW
N1 = 300 rpm
H1 = 45 m
\({N_s} = \frac{{N\sqrt P }}{{{H^{\frac{5}{4}}}}}\)
For the same power, \({N} \propto \frac{1}{{{H^{\frac{5}{4}}}}}\)
\(\begin{array}{l} {N_2} = {N_1}{\left( {\frac{{{H_1}}}{{{H_2}}}} \right)^{\frac{5}{4}}}\\ = 300 \times {\left( {\frac{{45}}{{60}}} \right)^{\frac{5}{4}}} \end{array}\)
⇒ 209.4 rpm
∴ Option 1 is more appropriate.