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In a power transformer, the core loss is 50 W at 40 Hz and 100 W at 60 Hz, under the condition of same maximum flux density in both cases. The core loss at 50 Hz will be
1. 64 W
2. 73 W
3. 82 W
4. 91 W

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Correct Answer - Option 2 : 73 W

Concept:

Hysteresis losses: These are due to the reversal of magnetization in the transformer core whenever it is subjected to alternating nature of magnetizing force.

\({W_h} = \eta B_{max}^xfv\)

\({B_{max}} \propto \frac{V}{f}\)

Where

x is the Steinmetz constant

Bm = maximum flux density

f = frequency of magnetization or supply frequency

v = volume of the core

At a constant V/f ratio, hysteresis losses are directly proportional to the frequency.

Wh  f

Eddy current losses: Eddy current loss in the transformer is I2R loss present in the core due to the production of eddy current.

\({W_e} = K{f^2}B_m^2{t^2}V\)

\({B_{max}} \propto \frac{V}{f}\)

Where,

K - coefficient of eddy current. Its value depends upon the nature of magnetic material

Bm - Maximum value of flux density in Wb/m2

t - Thickness of lamination in meters

f - Frequency of reversal of the magnetic field in Hz

V - Volume of magnetic material in m3

At a constant V/f ratio, eddy current losses are directly proportional to the square of the frequency.

We  f2

Iron losses or core losses or constant losses are the sum of both hysteresis and eddy current losses.

Wi = W + We

At constant V/f ratio, Wi = Af + Bf2

Calculation:

The table below shows the given data.

 

Frequency (f)

Core losses (W)

Case 1

40 Hz

50

Case 2

60 Hz

100

Case 3

50 Hz

Required value

 

The V/f ratio is constant in all the cases as shown in the above table.

Now, the equations for Case 1 and Case 2 are given below

Case 1: 50 = A (40) + B (40)2

Case 2: 100 = A (60) + B (60)2

By solving the above two equations,

A = 0.4166, B = 0.0208

Now, the required value for the Case 3 is

W= 0.4166 (50) + 0.0208 (50)2 = 72. 83 W

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