Correct Answer - Option 3 : 3
The bit energy is digital modulation is given by:
Eb = C × Tb
C = Carrier Power
Tb = Bit duration, which is the inverse of the bit rate, i.e.
\(T_b=\frac{1}{f_b}\)
The bit energy can now be written as:
\(E_b = \frac{C}{f_b}\)
Also, the total noise power over the complete Bandwidth (B) is defined as:
N = N0 × B
\(N_0 = \frac{N}{B}\)
where N0 = Noise power density
∴ The required ratio is given by:
\(\frac{E_b}{N_0} = \frac{C}{f_b}\times\frac{B}{N}\)