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Manometric head developed hm in m, and discharge Q in lps n respect of two pumps, 1 and 2, are tabulated. The pumps are connected in series against a static head of 100 m. Total head losses for a discharge of Q are as \(\frac{{{Q^2}}}{{100}}\left( m \right).\) What is the delivered discharge?

Q in lps

15

18

20

22

25

Hm1 in m

60.6

61.2

62.0

55.0

48.0

Hm2 in m

50.8

51.0

48.8

45.8

40.0


1. 20.15 lps
2. 21.25 lps
3. 21.95 lps
4. 22.20 lps

1 Answer

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Best answer
Correct Answer - Option 2 : 21.25 lps

When pumps are connected in series:

Total head = Sum of heads of all the pumps connected in series.

Required Head for a given discharge =Static head + head Loss

Pump will operate only when available head ≥ total required head

S No

Discharge, Q in lps

Available head (Hm1 + Hm2 ) in m

Required head = 100 +  in m

Remarks

1

15

111.4

102.25

Pump will work

2

18

112.2

103.24

Pump will work

3

20

110.8

104

Pump will work

4

22

100.8

104.82

Pump will not work

5

25

88

106.25

Pump will not work

 

The delivery discharge lies in between 20 to 22 lps. The exact solution can be obtained by plotting the graph between Q Vs available head and Q Vs required head, the point of intersection gives the exact delivery discharge and we may get Q = 21.25 lps. 

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