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Two trains start from A and B in the opposite direction at the same time toward each other. A faster train covers its journey in 4 hrs after meeting the slower train in the way and slower train covers its remaining journey in 125% extra time than the time taken by faster train after meeting point. If the speed of the slower train is 60 km/hr, then find the speed of the faster train?
1. 80 km/hr
2. 90 km/hr
3. 100 km/hr
4. 70 km/hr
5. None of these

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Best answer
Correct Answer - Option 2 : 90 km/hr

Given:

speed of the slower train = 60 km/hr

Formula:

Ratio of their speed (1st train to 2nd train) = √t2/√ t1

Where, t2 = time taken by 2nd train covers its remaining journey

t1 = time taken by 1st train covers its remaining journey

Percentage = (new value/original value) × 100

Calculation:

Time taken by 2nd train cover its journey after meeting = (225/100) × 4 = 9 hrs

\(\Rightarrow \frac{{speed\;of\;faster\;train}}{{speed\;of\;slower\;train}} = \frac{{\sqrt 9 }}{{\sqrt 4 }} = \frac{3}{2}\;\)

∴ The speed of the faster train = 3/2 × 60 = 90 km/hr 

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