Concept:
Phase Angle error, \(\beta = \frac{{180}}{\pi } \times \frac{{{I_\mu }\cos \delta - {I_w}\sin \delta }}{{n{I_s}}}\)
n is the number of secondary turns
Is is the secondary current
Iμ is the magnetizing current
Iw is the core loss current
Calculation:
Phase angle error, β = 3.438 mins
\(= \frac{{3.438}}{{60}} = 0.0573^\circ\)
Secondary turns (n) = 1000
Secondary current (Is) = 1 A
Load is UPF, so δ = 0
Hence, \(\beta = \frac{{180}}{\pi } \times \frac{{I\mu }}{{n{I_s}}}\)
\( \Rightarrow {I_\mu } = \frac{{\beta\; \times \;\pi\; \times \;n\; \times \;{I_s}}}{{180}} = \frac{{0.573\; \times \;\pi\; \times \;1000\; \times \;1}}{{180}} = 1\;A\)
Hence, the rms value of the magnetising current of CT is 1 Amp.