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A computer system has a cache with a cache access time TC = 10 ns, a hit ratio of 80 % and an average memory access time TM = 20 ns. What is the access time for physical memory TP?
1. 90 ns
2. 80 ns
3. 60 ns
4. 20 ns

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Correct Answer - Option 3 : 60 ns

Concept:

TM = h × TC + (1 – h) × TP

TM is the average memory access time

TC is the cache access time

TP is the access time for physical memory

h is the hit ratio

Calculation:

Given that TC = 10 ns, TM = 20 ns, h = 80% = 0.8

TM = h × TC + (1 – h) × TP

⇒ 20 = 0.8 × 10 + (1 – 0.8) × TP

⇒ 20 = 8 + 0.2 TP

⇒ TP = 60 ns

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