Concept:
ω1 = maximum angular speed, ω2 = minimum angular speed,
ΔKE = Change in Kinetic energy, If= Moment of Inertia of Flywheel
Therefore, \({\rm{\Delta KE\;}} = \frac{1}{2}\; \times {I_f} \times \left( {\omega _1^2 - \omega _2^2} \right)\)
Calculation:
ω1 = 110 rad/sec, ω2 = 100 rad/sec, ΔKE = 1.05 kJ = 1050 J
1050 = \(\frac{1}{2}\; \times {I_f}\; \times \left( {{{110}^2} - {{100}^2}\;} \right)\)
\({I_f} = 1\;kg.{m^2}\)