Correct Answer - Option 1 : AB’
Let f = (A + C) (AB' + AC) (AC' + B')
f = (A + C) ((AB' (AC' + B') + AC(AC' + B'))
f = (A + C) (AB'C' + AB' + AB'C) -----> (AA = A, CC' = 0, B'B' = B)
f = (A+C) (AB' (C' +1 + C))
f = (A + C) AB'
f = AB' + AB'C
f = AB'(1 + C)
f = AB'