Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
47 views
in Aptitude by (95.2k points)
closed by
a3 – b3 = 5528, a – b = 8 then find (a – b)2 + 3ab
1. 561
2. 661
3. 961
4. 691

1 Answer

0 votes
by (95.4k points)
selected by
 
Best answer
Correct Answer - Option 4 : 691

Given:

a3 – b3 = 5528

a – b = 8

Formula used:

a3 – b3 = (a – b) (a2 + ab + b2)

(a – b)2 = a2 + b2 – 2ab

Calculation:

(a – b)2 + 3ab = a2 + b2 – 2ab + 3ab

⇒ a2 + ab + b2

(a3 – b3)/(a – b) = (a – b)(a2 + ab + b2) / (a – b)

⇒ 5528/8

⇒ 691

∴ Required value is 691

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...