Correct Answer - Option 2 : 15.625 MHz
Concept:
Number of flip flops
For mod N counter a total number of flip-flops required is given by:
2n ≥ N
n: Total number of flip flops.
Maximum frequency
Let ‘n’ number of flip flops are used in a counter having the delay as ‘tpd’ then the total maximum frequency is defined by:
\(f_{max} = \frac{1}{n \times {t_{pd}}}\)
Calculation:
Given modulus of the counter is 8 and delay of each flip flop is 8 ns
The number of flip flops required is 8 (∵ 28 = 256)
The maximum frequency will be:
\({f_{max}} = \frac{1}{{8 \times 8ns}}\)
\({f_{max}} = \frac{1}{{64 \times {{10}^{ - 9}}sec}}\)
\({f_{max}} = \frac{{1000}}{{64}}MHz\)
fmax = 15.625 MHz