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What would be the maximum operating frequency of Mod-256 counter constructed with JK flip flops, having a propagation delay of 8ns each?


1. 16.525 MHz
2. 15.625 MHz
3. 25.625 MHz
4. 18.525 MHz

1 Answer

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Best answer
Correct Answer - Option 2 : 15.625 MHz

Concept:

Number of flip flops

For mod N counter a total number of flip-flops required is given by:

2n ≥ N

n: Total number of flip flops.

Maximum frequency

Let ‘n’ number of flip flops are used in a counter having the delay as ‘tpd’ then the total maximum frequency is defined by:

\(f_{max} = \frac{1}{n \times {t_{pd}}}\)

Calculation:

Given modulus of the counter is 8 and delay of each flip flop is 8 ns

The number of flip flops required is 8 (∵ 28 = 256)

The maximum frequency will be:

\({f_{max}} = \frac{1}{{8 \times 8ns}}\)

\({f_{max}} = \frac{1}{{64 \times {{10}^{ - 9}}sec}}\)

\({f_{max}} = \frac{{1000}}{{64}}MHz\)

fmax = 15.625 MHz

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