Steps of construction :
(1) Draw a line BC = 6.5 cm.
(2) From point B and C draw an are of 5.5 cm and 5 cm respectively and mark the intersecting point as A.
(3) Join AB and AC.
(4) Draw the bisectors of ∠B and ∠C. Let the bisectors meet at point O.
(5) From O, drop perpeudicular on side BC. Let OD be the perpendicular drawn on BC.
(6) With O as centre, and OD as radius. Draw a circle.
The circle so obtained is the required circle
Given that, BC = 6.5 cm, AB = 5.5 cm, AC = 5 cm
Radius of incircle is 2.5 cm
