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A cube strikes a stationary ball exerting an average force of 50 N over at time of 10 ms. The ball has mass of 0.20 kg. Its speed after the impact will be
1. 3.5 m/s
2. 2.5 m/s
3. 1.5 m/s
4. 0.5 m/s

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Correct Answer - Option 2 : 2.5 m/s

Concept:

Impulse is equal to change in momentum

F × t = m (v – u)

Where, v = velocity after the impact, u = velocity before the impact, t = fraction of time during which force is applied

Calculation:

Given, F = 50 N, t = 10 ms = 10 × 10-3 s

50 × 10 × 10-3 = 0.20 × (V – 0)

v = 2.5 m/s

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