Correct Answer - Option 2 : 3.93 × 10
-5 m
3/s
Concept:
The hydraulic liquid flow rate (Q) is calculated by:
Q = A × V
Where,
A = Cross sectional area of piston
V = velocity of the piston
Calculation:
Given:
Diameter of piston = 100 mm = 0.1 m
Displacement = 50 mm = 0.05 m
Time taken: 10 seconds
Now,
\(Area = \frac{\pi }{4} \times {d^2}\)
\(\therefore Area = \frac{\pi }{4} \times {0.1^2}\)
∴ Area = 0.0078 m2
\({\rm{Velocity\;}} = \frac{{Displacement}}{{time}}\)
\({\rm{Velocity\;}} = \frac{{0.05}}{{10}}\)
∴ Velocity = 0.005 m/s
Now,
Q = Area × Velocity
∴ Q = 0.0078 × 0.005
∴ Q = 3.926 × 10-5 m3/s
Hence option 2 is the correct answer.