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If a workpiece is moved by 50 mm in 10 s by a piston of diameter 100 mm, the hydraulic liquid flow rate is nearly
1. 3.00 × 10-5 m3/s
2. 3.93 × 10-5 m3/s
3. 4.74 × 10-5 m3/s
4. 5.00 × 10-5 m3/s

1 Answer

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Best answer
Correct Answer - Option 2 : 3.93 × 10-5 m3/s

Concept:

The hydraulic liquid flow rate (Q) is calculated by:

Q = A × V

Where,

A = Cross sectional area of piston

V = velocity of the piston

 

Calculation:

Given:

Diameter of piston = 100 mm = 0.1 m

Displacement = 50 mm = 0.05 m

Time taken: 10 seconds

Now,

\(Area = \frac{\pi }{4} \times {d^2}\)

\(\therefore Area = \frac{\pi }{4} \times {0.1^2}\)

Area = 0.0078 m2

\({\rm{Velocity\;}} = \frac{{Displacement}}{{time}}\)

\({\rm{Velocity\;}} = \frac{{0.05}}{{10}}\)

Velocity = 0.005 m/s

Now,

Q = Area × Velocity

Q = 0.0078 × 0.005

Q = 3.926 × 10-5 m3/s 

Hence option 2 is the correct answer.

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