Correct Answer - Option 4 : 250, 125
Concept:
Hoop stress for a cylindrical vessel \({{\sigma }_{h}}=\frac{PD}{2t}\)
Axial stress for a cylindrical vessel \({{\sigma }_{L}}=~\frac{PD}{4t}\)
Where P = Internal pressure, D = Internal Diameter, t = thickness
Calculation:
Given, P = 5 MPa, D = 200 mm, t = 2 mm
Hoop stress \({{\sigma }_{h}}=\frac{PD}{2t}=\frac{5\times 200}{2\times 2}=250~MPa\)
Axial stress
\({{\sigma }_{l}}=\frac{PD}{4t}=\frac{5\times 200}{4\times 2}=125~MPa\)
