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\(If\;x\; = \;4\; + \;\sqrt {15} ,\;find\;the\;value\;of\;{x^3}\; + \;\frac{1}{{{x^3}}}\)
1. 80
2. 48
3. 488
4. 536

1 Answer

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Best answer
Correct Answer - Option 3 : 488

Calculation:

Given: x = 4 + √15,

⇒ 1/x = 1/(4 + √15) = 4 - √15

\( \Rightarrow {\rm{\;}}x\; + \;\frac{1}{x}\; = \;4{\rm{\;}} + {\rm{\;}}\sqrt {15} \; + \;4 - {\rm{\;}}\sqrt {15} \; = \;8\) 

\( \Rightarrow {\rm{\;}}{\left( {x\; + \;\frac{1}{x}} \right)^3}\; = \;{x^3}\; + \;\frac{1}{{{x^3}}}\; + \;3\left( {x\; + \;\frac{1}{x}} \right)\) 

\( \Rightarrow {\rm{\;}}{\left( 8 \right)^3}\; = \;{x^3}\; + \;\frac{1}{{{x^3}}}\; + \;3\left( 8 \right)\)

\( \Rightarrow {\rm{\;}}{x^3}\; + \;\frac{1}{{{x^3}}}\; = \;512 - 24\; = \;488\)

∴ Required answer is 488.

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