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25 mL of the given HCl solution requires 30mL of 0.1M sodium carbonate solution. What is the volume of this HCl solution required to titrate 30mL of 0.2M aqueous NaOH solution?
1. 75 ml
2. 25 ml
3. 12.5 ml
4. 50 ml

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Correct Answer - Option 2 : 25 ml


The reaction of HCl with Na2CO3 is as follows:

2HCl + Na2CO3 →  2NaCl + H2O + CO2

We know that, Meq of HCl = Meq of Na2CO3

\(\frac{{25}}{{1000}} \times 1 \times {M_{{\rm{HCl}}}} = \frac{{30}}{{1000}} \times 0.1 \times 2\)

\({M_{{\rm{HCl}}}} = \frac{{30 \times 0.2}}{{25}} = \frac{6}{{25}}{\rm{M}}\)

The reaction of HC with NaOH is as follows:

NaOH + HC →  NaC + H2O

Also, Meq of HCl = Meq of NaOH

\(\frac{6}{{25}} \times 1 \times \frac{V}{{1000}} = \frac{{30}}{{1000}} \times 0.2 \times 1\)

V = 25 ml.

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