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The correct order for acid strength of compounds CH ≡ CH, CH3 – C ≡ CH and CH2 = CH2 is as follows: 
1. CH3 – C ≡ CH > CH2 = CH2 > HC ≡ CH
2. CH3 – C ≡ CH > CH ≡ CH > CH2 = CH2
3. HC ≡ CH > CH3 – C ≡ CH > CH2 = CH2
4. CH ≡ CH > CH2 = CH2 > CH3 – C ≡ CH

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Correct Answer - Option 3 : HC ≡ CH > CH3 – C ≡ CH > CH2 = CH2

Concept:

Ethane (H2C=CH2) is a sp2 -hybridized and ethyne (HC ≡ CH) is sp- hybridized. In ethane, the sp -hybridised carbon atom possesses maximum s-character and hence, maximum electronegativity. Due to which, it attracts the shared electron pair of C–H bond to a greater extend and makes the removal of proton easier. Hence, alkyne is much more acidic than alkene. Hence, the correct order of acidic strength is:

HC≡CH>H3 C-C≡CH>CH2=CH2

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