Question

A ball is thrown vertically upwards with a velocity of 50 ms^-1. Calculate the maximum height to which it rises.
1. 144.69 m
2. 127.55 m
3. 126 m
4. 200 m

Answer 1

Correct Answer - Option 2 : 127.55 m

The initial velocity of ball u = 50 ms^-1

Final velocity v =0

The value of g = 9.8 m/s²

At the maximum height, the velocity becomes zero, so the final velocity also zero.

Now, v² = u² - 2gh

(0)² = (50)² - 2 x 9.8 x h

h =2500 / 19.6 = 127.55 m