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Elevation in the boiling point for 1 molal solution of glucose is 2K. The depression in the freezing point for 2 molal solution of glucose in the same solvent is 2K. The relation between Kb and Kf is
1. Kb = 1.5 Kf
2. Kb = 0.5Kf
3. Kb = Kf
4. Kb = 2Kf

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Correct Answer - Option 4 : Kb = 2Kf

Concept:

Elevation in boiling point (ΔTb) = Kb × m × i

Depression is freezing point (ΔTf) = Kf × m × i

Where, m = molality 

For the glucose solution (Van’t Hoff factor, i = 1)

\(\Delta T_{b}^{1~m}=\Delta T_{f}^{2m}=2K\)

So, Kb × 1 × 1 = Kf × 2 × 1

⇒ Kb = 2Kf

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