Question

The ground state energy of hydrogen atom is -13.6 eV. The energy of second excited state of He⁺ ion in eV is
1. -54.4
2. -3.4
3. -6.04
4. -27.2

Answer 1

Correct Answer - Option 3 : -6.04

Concept:

The ground state energy of H-atom is +13.6 eV 

For second excited state, n = 2 + 1 = 3

Calculation:

\(\therefore {{E}_{3}}\left( H{{e}^{+}} \right)=-13.6\times \frac{{{Z}^{2}}}{{{n}^{2}}}eV~\left[ \because for~H{{e}^{+}},~Z=2 \right]\) 

\(-13.6\times \frac{{{2}^{2}}}{{{3}^{2}}}eV=-6.04~eV\)