Correct Answer - Option 2 : of the rotor circuit is very high and the motor is under no-load
For induction motor,
The effective resistance of the rotor is given as \(\frac{{{R_2}}}{s}\)
Where,
R2 is standstill rotor resistance
s is slip
As s → 0, \(\frac{{{R_2}}}{s} \approx \infty\) i.e., open circuit.
Slip ≈ 0 when the rotor speed is almost equal to synchronous speed Ns.
This is possible at no load.