Question

Consider the following C program:

#include <stdio.h>

int main ( )

{

int arr [ ] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0, 1, 2, 5}, *ip = arr + 4;

printf (“ % d \n”, ip[1]);

return 0;

}

The number that will be displayed on execution of the program is _________.

Answer 1

int  *ip = arr + 4 //ip is a integer pointer pointing to 5 element of the array

ip[1] = *(ip + 1xsizeofint) = *(address of 6^th element) = 6