Correct Answer - Option 3 : 1111 1111 1110 0100
2
|
28
|
|
2
|
14
|
0
|
2
|
7
|
0
|
2
|
3
|
1
|
2
|
1
|
1
|
|
0
|
1
|
2810 = (11100)2 = (0000 0000 0001 1100)2
-2810 = 2’s complement of 0000 0000 0001 1100
2’s complement of 0000 0000 0001 1100 = 1111 1111 1110 0100
Note:
Tricks to find: 2’s complement
Start reading the bits from LSB (right hand side) and write it unless first 1 is encounter, leave the first 1 as it is and complement the remaining bits.