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Budhan covers a distance of 19 km in 2 hours by cycling one fourth of the time and walking the rest. The next day he cycles (at the same speed as before) for half the time and walks the rest (at the same speed as before) and covers 26 km in 2 hours. The speed in km/h at which Budhan walks is
1. 1
2. 4
3. 5
4. 6

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Correct Answer - Option 4 : 6

Let Budhan cycles at a speed of x km/hr and walks at a speed of y km/hr.

Budhan covers a distance of 19 km in 2 hours by cycling one fourth of the time and walking the rest.

I.e. Budhan cycled for half an hour and had walk for remaining time.

⇒ 0.5x + 1.5y = 19       ----(1)

The next day he cycles (at the same speed as before) for half the time and walks the rest (at the same speed as before) and covers 26 km in 2 hours.

⇒ x + y = 26      ----(2)

By solving the equations (1) and (2), x = 20 km/hr and y = 6 km/hr

So, the speed at which Budhan walks is 6 km/hr.

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