Question

The magnetic flux density of an electromagnetic flowmeter is 100 mWb/m². The electrodes are wall-mounted inside the pipe having a diameter of 0.25 m. A voltage of 1 V is generated when a conducing fluid is passed through the flowmeter. The volumetric flowrate of the fluid in m³/s is _________.

Answer 1

Given that, magnetic flux density (B) = 100 × 10^-3 Wb/m²

Diameter (D) = 0.25 m

Generated voltage (e) = 1 V

We know that

e = BDV

⇒ 1 = 100 × 10^-3 × 0.25 × V

⇒ V = 40 m/s

Volumetric flow rate is given by

Q = AV

<!--[if gte msEquation 12]>=πD24×V<![endif]--><!--[if !msEquation]--><!--[endif]-->

<!--[if gte msEquation 12]>=π×0.2524×40=1.96m3sec<![endif]--><!--[if !msEquation]--><!--[endif]-->\(= \frac{{\pi {D^2}}}{4} \times V\)

\(= \frac{{\pi \times {{\left( {0.25} \right)}^2}}}{4} \times 40 = 1.96{m^3}/sec\)