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The only function among the following that is analytic, is
1. f(z) = Re(z)
2. \(f\left( z \right) = \bar z\)
3. f(z) = Im (z)
4. f(z) = sin(z)

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Correct Answer - Option 4 : f(z) = sin(z)

i) f(z) = Re(z) = Re(x + iy) = x

here u = x, v = 0

ux = 1, vy = 0

f(z) is not satisfying CR equations Hence f(z) is not analytic.

ii) f(z) = z̅ = x - fy

u = x, v = -y

ux = 1, vy = -1

ux ≠ vy

f(x) is not satisfying CR equations.

Hence f(z) is not analytic

iii) f(z) = Im (z) = Im (x + iy) = y

u = 0, v = y

ux = 0, vy = 1

f(x) is not satisfying CR equations.

Hence f(z) is not analytic

iv) f(z) = sin z = (x + iy)

= sin x cos iy + cos x sin iy

= sin x cos hy + i cos x sin hy

u = sin x cos hy, v = cos x sin hy

ux = cos x cos hy

vy = cos x cos hy

uy = sin x sin hy

vx = - sin x sin hy

ux = vy and uy = - vx

f(z) is satisfying CR equation.

Hence f(z) is analytic.

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