The value of the definite integral ∫ (1 + e^(-x^2)) dx is

Question

The value of the definite integral ∫ (1 + e^{-x^2}) (for x → 0,1) dx is

(a) -1

(b) 2

(c) 1 + e^-1

(d) None of these

Answer 1

Correct option (d) None of these

Explanation :

If f(x) is a continuous function defined on [a, b], then

Where M and m are maximum and minimum values respectively of f(x) in [a, b].