Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
65 views
in Algebra by (115k points)
closed by
The set of values of \(p\) for which the roots of the equation \(3x^2+2x+p(p–1) = 0\) are of opposite sign is
1. \((–∞, 0)\)
2. \((0, ∞)\)
3. \((1, ∞)\)
4. (0, 1)

1 Answer

0 votes
by (152k points)
selected by
 
Best answer
Correct Answer - Option 4 : (0, 1)

p(p−1) < 0, because product of roots is a negative number.

Thus p must be less than 1 and greater than 0

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...