Correct Answer - Option 2 : 5 m/s
Concept:
To study the effect on model and prototype, the Reynolds number of both should be the same.
\({\left( {Re} \right)_m} = {\left( {Re} \right)_p}\)
\({\left( {\frac{{\rho VD}}{\mu }} \right)_m} = {\left( {\frac{{\rho VD}}{\mu }} \right)_p}\;\)
\( \Rightarrow {\left( {V \times D} \right)_m} = {\left( {V \times D} \right)_p}\)
V × 10D = (50 × D)
⇒ V = 5 m/s