Correct Answer - Option 3 : 5.00

V = 2.87 m^{3}; T = 300 K

P_{gauge} = 0.5 bar; P_{atm} = 1 bar; R = 287 j/Kg-K

PV = mRT (P is absolute pressure)

P_{abs} = P_{atm} + P_{gauge} = 0.5 + 1 = 1.5 bar = 150 kPa

\(PV = mRT \Rightarrow m = \frac{{PV}}{{RT}} = \frac{{150*2.87}}{{0.287*300}}\)

m = 5 Kg