Question

An electric motor is developing 10 kW at a speed of 900 rpm. The torque available at the shaft is
1. 106 N-m
2. 1.7 N-m
3. 10,000 N-m
4. 450 N-m

Answer 1

Correct Answer - Option 1 : 106 N-m

Given \(P = 10\;kW,\;N = 900\;rpm\)

\(\begin{array}{l} P = \tau \omega \\ \Rightarrow \tau = \frac{{P \times 60}}{{2\pi {N_s}}} = \frac{{10 \times {{10}^3} \times 60}}{{2\pi \times 900}} = 106.1\;N - m \end{array}\)