Correct Answer - Option 2 : 3 × 10
20
CONCEPT:
Electric current:
- The flow of electric charges through a conductor constitutes an electric current.
- Quantitatively, electric current in a conductor across an area held perpendicular to the direction of flow of charge is defined as the amount of charge flowing across that area per unit time i.e.,
\(⇒ {\rm{Electric\;curernt\;}}\left( {\rm{I}} \right) = \frac{{{\rm{Electric\;charge}}\;\left( {\rm{Q}} \right)}}{{{\rm{Time\;}}\left( {\rm{t}} \right)}}\)
- SI unit of current is ampere and it is denoted by the letter A.
EXPLANATION:
Given - Current (I) = 1.6 A
- The amount of charge flowing across that area,
⇒ Q = current passed × time(sec)
⇒ Q = it = 1.6 × 60 = 96 C
- Total charge = Number of ions neutralised(n) × valency(v) × electon charge(e)
- Let n be the number of Cu + 2 ions, then
\(⇒ n = \frac{Q}{{v\; \times \;e}} = \;\frac{{96}}{{2\; \times \;1.6\; \times \;{{10}^{ - 19}}}} = 3\; \times \;{10^{20}}\;\)