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The laboratory tests on a soil sample yields the following results: natural moisture content = 18%, liquid limit = 60%, plastic limit = 25%, percentage of clay sized fraction = 25%. The liquidity index and activity (as per the expression proposed by Skempton) of the soil, respectively, are
1. -0.2 and 1.4
2. 0.2 and 1.4
3. -1.2 and 0.714
4. 1.2 and 0.714

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Correct Answer - Option 1 : -0.2 and 1.4

Given ⇒ WLL = 60% = 0.6

WPL = 25% = 0.25

% of clay sized fraction 25% = 0.25, Natural moisture content wn = 18% = 0.18

\(\begin{array}{l} {I_L} = \frac{{{W_n} - {W_{PL}}}}{{{W_{LL}} - {W_{PL}}}}\\ = \frac{{0.18 - 0.25}}{{0.6 - 0.25}} = - 0.2\\ Activity = \frac{{{I_P}}}{{\% \;of\;clay\;sized\;fraction}}\\ = \frac{{{W_{LL}} - {W_{PL}}}}{{0.25}} = \frac{{0.6 - 0.25}}{{0.25}} = 1.4 \end{array}\)

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