Concept:
Outlet concentration Lt = L0 e- Kt
\(Detention\;Time\;\left( {{t_d}} \right) = \frac{{volume}}{{Discharge}} \)
Note that if decay constant is assumed to have been given at base ‘e’
Calculation:
Given ⇒ Initial concentration \(\left( {{L_0}} \right) = 54\frac{{mg}}{l}\)
Q = 0.8 m3/day
V = 2 × 4 × 2 = 16 m3
\(Detention\;Time\;\left( {{t_d}} \right) = \frac{{16}}{{0.8}} = 20\;day\)
Outlet concentration Lt = L0 e- Kt
L
t = L
0e
-Kt = 54e
-0.1 × 20 = 7.3 mg/l